Practice Problem 13.8 Reflected Impedance

In the ideal transformer circuit of Fig. 13.38, find $V_{o}$ and the complex power supplied by the source.

Jawab

$$Z_{R}= \frac{16-j24}{4^2}=1-j1.5 \Omega$$

$Z_{In}=2+Z_{R}=3-j1.5 \Omega$

$I_{1}=240/(3-j1.5) = 64+j32=71.55\angle26.57^\circ A$

$I_{2}=\frac{-I_{1}}{n}=\frac{64+j32}{4}=16+j8=17.89\angle26.57^\circ A$

Maka $V_{o}$,

$V_{o}= -j24 I_{2}= -j24(16+j8)=(24\angle-90^\circ)(17.89\angle26.57^\circ)$
$=192-j384=429.33 \angle 296.57^\circ V =429.33 \angle -63.43^\circ V$

$S_{1}=V_{1}I_{1}*=240(64+j32)=(240\angle0^\circ)(71.55\angle-26.57^\circ)=17172\angle-26.57^\circ VA$
$S_{1}=17.17\angle-26.57^\circ kVA$